131211222023407 has 2 divisors, whose sum is σ = 131211222023408. Its totient is φ = 131211222023406.

The previous prime is 131211222023333. The next prime is 131211222023489. The reversal of 131211222023407 is 704320222112131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131211222023407 is a prime.

It is a super-2 number, since 2×131211222023407² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131211222023507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605611011703 + 65605611011704.

It is an arithmetic number, because the mean of its divisors is an integer number (65605611011704).

Almost surely, 2^{131211222023407} is an apocalyptic number.

131211222023407 is a deficient number, since it is larger than the sum of its proper divisors (1).

131211222023407 is an equidigital number, since it uses as much as digits as its factorization.

131211222023407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 31.

Adding to 131211222023407 its reverse (704320222112131), we get a palindrome (835531444135538).

The spelling of 131211222023407 in words is "one hundred thirty-one trillion, two hundred eleven billion, two hundred twenty-two million, twenty-three thousand, four hundred seven".