Base | Representation |
---|---|
bin | 11101110101010111111110… |
… | …010110010111000101100111 |
3 | 122012120200002202011000222011 |
4 | 131311113332112113011213 |
5 | 114144231041114400403 |
6 | 1143021334230415051 |
7 | 36431461300062514 |
oct | 3565277626270547 |
9 | 565520082130864 |
10 | 131211223200103 |
11 | 38898404910702 |
12 | 12871745201487 |
13 | 582a21c0b56a7 |
14 | 245892b09830b |
15 | 1028189711a6d |
hex | 7755fe597167 |
131211223200103 has 4 divisors (see below), whose sum is σ = 138117077052760. Its totient is φ = 124305369347448.
The previous prime is 131211223200089. The next prime is 131211223200151. The reversal of 131211223200103 is 301002322112131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 131211223200103 - 225 = 131211189645671 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131211223200503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3452926926300 + ... + 3452926926337.
It is an arithmetic number, because the mean of its divisors is an integer number (34529269263190).
Almost surely, 2131211223200103 is an apocalyptic number.
131211223200103 is a deficient number, since it is larger than the sum of its proper divisors (6905853852657).
131211223200103 is an equidigital number, since it uses as much as digits as its factorization.
131211223200103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6905853852656.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 131211223200103 its reverse (301002322112131), we get a palindrome (432213545312234).
The spelling of 131211223200103 in words is "one hundred thirty-one trillion, two hundred eleven billion, two hundred twenty-three million, two hundred thousand, one hundred three".
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