131211233242301 has 4 divisors (see below), whose sum is σ = 135443853669504. Its totient is φ = 126978612815100.

The previous prime is 131211233242261. The next prime is 131211233242343. The reversal of 131211233242301 is 103242332112131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131211233242301 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131211233442301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2116310213555 + ... + 2116310213616.

It is an arithmetic number, because the mean of its divisors is an integer number (33860963417376).

Almost surely, 2^{131211233242301} is an apocalyptic number.

It is an amenable number.

131211233242301 is a deficient number, since it is larger than the sum of its proper divisors (4232620427203).

131211233242301 is an equidigital number, since it uses as much as digits as its factorization.

131211233242301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4232620427202.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 131211233242301 its reverse (103242332112131), we get a palindrome (234453565354432).

The spelling of 131211233242301 in words is "one hundred thirty-one trillion, two hundred eleven billion, two hundred thirty-three million, two hundred forty-two thousand, three hundred one".