131211233242303 has 4 divisors (see below), whose sum is σ = 131211288079560. Its totient is φ = 131211178405048.

The previous prime is 131211233242261. The next prime is 131211233242343. The reversal of 131211233242303 is 303242332112131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131211233242303 - 2³³ = 131202643307711 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131211233242343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23657548 + ... + 28672321.

It is an arithmetic number, because the mean of its divisors is an integer number (32802822019890).

Almost surely, 2^{131211233242303} is an apocalyptic number.

131211233242303 is a deficient number, since it is larger than the sum of its proper divisors (54837257).

131211233242303 is an equidigital number, since it uses as much as digits as its factorization.

131211233242303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54837256.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 131211233242303 its reverse (303242332112131), we get a palindrome (434453565354434).

The spelling of 131211233242303 in words is "one hundred thirty-one trillion, two hundred eleven billion, two hundred thirty-three million, two hundred forty-two thousand, three hundred three".