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13121131206949 is a prime number
BaseRepresentation
bin1011111011110000000001…
…0111010101100100100101
31201110100221012020101222121
42332330000113111210211
53204434034042110244
643523433042425541
72522653602023263
oct276740027254445
951410835211877
1013121131206949
1141a9705554397
12157ab683622b1
1374241832b8bc
143350cd6b1433
1517b49dad9c84
hexbef005d5925

13121131206949 has 2 divisors, whose sum is σ = 13121131206950. Its totient is φ = 13121131206948.

The previous prime is 13121131206919. The next prime is 13121131206971. The reversal of 13121131206949 is 94960213112131.

13121131206949 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9643465684449 + 3477665522500 = 3105393^2 + 1864850^2 .

It is a cyclic number.

It is not a de Polignac number, because 13121131206949 - 25 = 13121131206917 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13121131206919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560565603474 + 6560565603475.

It is an arithmetic number, because the mean of its divisors is an integer number (6560565603475).

Almost surely, 213121131206949 is an apocalyptic number.

It is an amenable number.

13121131206949 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121131206949 is an equidigital number, since it uses as much as digits as its factorization.

13121131206949 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69984, while the sum is 43.

The spelling of 13121131206949 in words is "thirteen trillion, one hundred twenty-one billion, one hundred thirty-one million, two hundred six thousand, nine hundred forty-nine".