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131211323351 is a prime number
BaseRepresentation
bin111101000110011001…
…1011110011111010111
3110112200100020211212122
41322030303132133113
54122210044321401
6140135550010155
712323352563213
oct1721463363727
9415610224778
10131211323351
115071240a309
122151a4a695b
13c4b0b32004
1464ca305943
15362e38921b
hex1e8ccde7d7

131211323351 has 2 divisors, whose sum is σ = 131211323352. Its totient is φ = 131211323350.

The previous prime is 131211323279. The next prime is 131211323389. The reversal of 131211323351 is 153323112131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131211323351 - 222 = 131207129047 is a prime.

It is a super-2 number, since 2×1312113233512 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131211323351.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131211328351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605661675 + 65605661676.

It is an arithmetic number, because the mean of its divisors is an integer number (65605661676).

Almost surely, 2131211323351 is an apocalyptic number.

131211323351 is a deficient number, since it is larger than the sum of its proper divisors (1).

131211323351 is an equidigital number, since it uses as much as digits as its factorization.

131211323351 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1620, while the sum is 26.

Adding to 131211323351 its reverse (153323112131), we get a palindrome (284534435482).

The spelling of 131211323351 in words is "one hundred thirty-one billion, two hundred eleven million, three hundred twenty-three thousand, three hundred fifty-one".