Base | Representation |
---|---|
bin | 111101000110011001… |
… | …1011110011111010111 |
3 | 110112200100020211212122 |
4 | 1322030303132133113 |
5 | 4122210044321401 |
6 | 140135550010155 |
7 | 12323352563213 |
oct | 1721463363727 |
9 | 415610224778 |
10 | 131211323351 |
11 | 5071240a309 |
12 | 2151a4a695b |
13 | c4b0b32004 |
14 | 64ca305943 |
15 | 362e38921b |
hex | 1e8ccde7d7 |
131211323351 has 2 divisors, whose sum is σ = 131211323352. Its totient is φ = 131211323350.
The previous prime is 131211323279. The next prime is 131211323389. The reversal of 131211323351 is 153323112131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131211323351 - 222 = 131207129047 is a prime.
It is a super-2 number, since 2×1312113233512 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131211323351.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131211328351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605661675 + 65605661676.
It is an arithmetic number, because the mean of its divisors is an integer number (65605661676).
Almost surely, 2131211323351 is an apocalyptic number.
131211323351 is a deficient number, since it is larger than the sum of its proper divisors (1).
131211323351 is an equidigital number, since it uses as much as digits as its factorization.
131211323351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1620, while the sum is 26.
Adding to 131211323351 its reverse (153323112131), we get a palindrome (284534435482).
The spelling of 131211323351 in words is "one hundred thirty-one billion, two hundred eleven million, three hundred twenty-three thousand, three hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •