Base | Representation |
---|---|
bin | 1011111011110000000001… |
… | …1110101011111000001011 |
3 | 1201110100221022212021110210 |
4 | 2332330000132223320023 |
5 | 3204434040040231243 |
6 | 43523433152012203 |
7 | 2522653624265445 |
oct | 276740036537013 |
9 | 51410838767423 |
10 | 13121133133323 |
11 | 41a970664a736 |
12 | 157ab68b31063 |
13 | 742418854677 |
14 | 3350cda53495 |
15 | 17b49dd6a933 |
hex | bef007abe0b |
13121133133323 has 4 divisors (see below), whose sum is σ = 17494844177768. Its totient is φ = 8747422088880.
The previous prime is 13121133133321. The next prime is 13121133133331. The reversal of 13121133133323 is 32333133112131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13121133133323 - 21 = 13121133133321 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13121133133321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2186855522218 + ... + 2186855522223.
It is an arithmetic number, because the mean of its divisors is an integer number (4373711044442).
Almost surely, 213121133133323 is an apocalyptic number.
13121133133323 is a deficient number, since it is larger than the sum of its proper divisors (4373711044445).
13121133133323 is an equidigital number, since it uses as much as digits as its factorization.
13121133133323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4373711044444.
The product of its digits is 8748, while the sum is 30.
Adding to 13121133133323 its reverse (32333133112131), we get a palindrome (45454266245454).
The spelling of 13121133133323 in words is "thirteen trillion, one hundred twenty-one billion, one hundred thirty-three million, one hundred thirty-three thousand, three hundred twenty-three".
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