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13121133133323 = 34373711044441
BaseRepresentation
bin1011111011110000000001…
…1110101011111000001011
31201110100221022212021110210
42332330000132223320023
53204434040040231243
643523433152012203
72522653624265445
oct276740036537013
951410838767423
1013121133133323
1141a970664a736
12157ab68b31063
13742418854677
143350cda53495
1517b49dd6a933
hexbef007abe0b

13121133133323 has 4 divisors (see below), whose sum is σ = 17494844177768. Its totient is φ = 8747422088880.

The previous prime is 13121133133321. The next prime is 13121133133331. The reversal of 13121133133323 is 32333133112131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13121133133323 - 21 = 13121133133321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13121133133321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2186855522218 + ... + 2186855522223.

It is an arithmetic number, because the mean of its divisors is an integer number (4373711044442).

Almost surely, 213121133133323 is an apocalyptic number.

13121133133323 is a deficient number, since it is larger than the sum of its proper divisors (4373711044445).

13121133133323 is an equidigital number, since it uses as much as digits as its factorization.

13121133133323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4373711044444.

The product of its digits is 8748, while the sum is 30.

Adding to 13121133133323 its reverse (32333133112131), we get a palindrome (45454266245454).

The spelling of 13121133133323 in words is "thirteen trillion, one hundred twenty-one billion, one hundred thirty-three million, one hundred thirty-three thousand, three hundred twenty-three".

Divisors: 1 3 4373711044441 13121133133323