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131212004023241 is a prime number
BaseRepresentation
bin11101110101011000101100…
…111000111101101111001001
3122012120202010011101221221122
4131311120230320331233021
5114144234141012220431
61143021543522245025
736431516531006021
oct3565305470755711
9565522104357848
10131212004023241
1138898775643689
12128719227b6775
13582a314ab2a0b
1424589a2a70a81
1510281d304ba7b
hex77562ce3dbc9

131212004023241 has 2 divisors, whose sum is σ = 131212004023242. Its totient is φ = 131212004023240.

The previous prime is 131212004023193. The next prime is 131212004023301. The reversal of 131212004023241 is 142320400212131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131185617269641 + 26386753600 = 11453629^2 + 162440^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131212004023241 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131212004023241.

It is not a weakly prime, because it can be changed into another prime (131212004023141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606002011620 + 65606002011621.

It is an arithmetic number, because the mean of its divisors is an integer number (65606002011621).

Almost surely, 2131212004023241 is an apocalyptic number.

It is an amenable number.

131212004023241 is a deficient number, since it is larger than the sum of its proper divisors (1).

131212004023241 is an equidigital number, since it uses as much as digits as its factorization.

131212004023241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 131212004023241 its reverse (142320400212131), we get a palindrome (273532404235372).

The spelling of 131212004023241 in words is "one hundred thirty-one trillion, two hundred twelve billion, four million, twenty-three thousand, two hundred forty-one".