Base | Representation |
---|---|
bin | 11101110101011000101101… |
… | …010101001001111000010011 |
3 | 122012120202010200022101210211 |
4 | 131311120231111021320103 |
5 | 114144234144410204021 |
6 | 1143021544344504551 |
7 | 36431516650554364 |
oct | 3565305525117023 |
9 | 565522120271724 |
10 | 131212011413011 |
11 | 38898779830731 |
12 | 1287192517b157 |
13 | 582a31649c469 |
14 | 24589a3a35b6b |
15 | 10281d3a0b3e1 |
hex | 77562d549e13 |
131212011413011 has 2 divisors, whose sum is σ = 131212011413012. Its totient is φ = 131212011413010.
The previous prime is 131212011412997. The next prime is 131212011413069. The reversal of 131212011413011 is 110314110212131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131212011413011 - 245 = 96027639324179 is a prime.
It is a super-2 number, since 2×1312120114130112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131212011413071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606005706505 + 65606005706506.
It is an arithmetic number, because the mean of its divisors is an integer number (65606005706506).
Almost surely, 2131212011413011 is an apocalyptic number.
131212011413011 is a deficient number, since it is larger than the sum of its proper divisors (1).
131212011413011 is an equidigital number, since it uses as much as digits as its factorization.
131212011413011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 22.
Adding to 131212011413011 its reverse (110314110212131), we get a palindrome (241526121625142).
The spelling of 131212011413011 in words is "one hundred thirty-one trillion, two hundred twelve billion, eleven million, four hundred thirteen thousand, eleven".
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