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131212011412997 is a prime number
BaseRepresentation
bin11101110101011000101101…
…010101001001111000000101
3122012120202010200022101210022
4131311120231111021320011
5114144234144410203442
61143021544344504525
736431516650554344
oct3565305525117005
9565522120271708
10131212011412997
1138898779830719
121287192517b145
13582a31649c458
1424589a3a35b5b
1510281d3a0b3d2
hex77562d549e05

131212011412997 has 2 divisors, whose sum is σ = 131212011412998. Its totient is φ = 131212011412996.

The previous prime is 131212011412961. The next prime is 131212011413011. The reversal of 131212011412997 is 799214110212131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82027962911041 + 49184048501956 = 9056929^2 + 7013134^2 .

It is a cyclic number.

It is not a de Polignac number, because 131212011412997 - 222 = 131212007218693 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131212011412397) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606005706498 + 65606005706499.

It is an arithmetic number, because the mean of its divisors is an integer number (65606005706499).

Almost surely, 2131212011412997 is an apocalyptic number.

It is an amenable number.

131212011412997 is a deficient number, since it is larger than the sum of its proper divisors (1).

131212011412997 is an equidigital number, since it uses as much as digits as its factorization.

131212011412997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54432, while the sum is 44.

The spelling of 131212011412997 in words is "one hundred thirty-one trillion, two hundred twelve billion, eleven million, four hundred twelve thousand, nine hundred ninety-seven".