Base | Representation |
---|---|
bin | 10011000110000000011… |
… | …101011000101010100100 |
3 | 11122102210220200000121210 |
4 | 103012000131120222210 |
5 | 132444210233242012 |
6 | 2442440225511420 |
7 | 163540363531662 |
oct | 23060035305244 |
9 | 4572726600553 |
10 | 1312120212132 |
11 | 46651571aa34 |
12 | 19236a4a2570 |
13 | 9696a12b5b2 |
14 | 47715139c32 |
15 | 241e7ede23c |
hex | 13180758aa4 |
1312120212132 has 96 divisors (see below), whose sum is σ = 3197624644480. Its totient is φ = 418351288320.
The previous prime is 1312120212119. The next prime is 1312120212191. The reversal of 1312120212132 is 2312120212131.
It is a junction number, because it is equal to n+sod(n) for n = 1312120212099 and 1312120212108.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 54616419 + ... + 54640437.
Almost surely, 21312120212132 is an apocalyptic number.
1312120212132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1312120212132 is an abundant number, since it is smaller than the sum of its proper divisors (1885504432348).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312120212132 is a wasteful number, since it uses less digits than its factorization.
1312120212132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26141 (or 26139 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 1312120212132 its reverse (2312120212131), we get a palindrome (3624240424263).
Subtracting 1312120212132 from its reverse (2312120212131), we obtain a palindrome (999999999999).
The spelling of 1312120212132 in words is "one trillion, three hundred twelve billion, one hundred twenty million, two hundred twelve thousand, one hundred thirty-two".
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