Base | Representation |
---|---|
bin | 111101000110011011… |
… | …0001000110111101111 |
3 | 110112200101120022012001 |
4 | 1322030312020313233 |
5 | 4122210234134411 |
6 | 140140012553131 |
7 | 12323361530644 |
oct | 1721466106757 |
9 | 415611508161 |
10 | 131212021231 |
11 | 50712846675 |
12 | 2151a7827a7 |
13 | c4b1017865 |
14 | 64ca447dcb |
15 | 362e475dc1 |
hex | 1e8cd88def |
131212021231 has 2 divisors, whose sum is σ = 131212021232. Its totient is φ = 131212021230.
The previous prime is 131212021151. The next prime is 131212021249. The reversal of 131212021231 is 132120212131.
It is a strong prime.
It is an emirp because it is prime and its reverse (132120212131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131212021231 is a prime.
It is a super-2 number, since 2×1312120212312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131212021199 and 131212021208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131212021271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606010615 + 65606010616.
It is an arithmetic number, because the mean of its divisors is an integer number (65606010616).
Almost surely, 2131212021231 is an apocalyptic number.
131212021231 is a deficient number, since it is larger than the sum of its proper divisors (1).
131212021231 is an equidigital number, since it uses as much as digits as its factorization.
131212021231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 131212021231 its reverse (132120212131), we get a palindrome (263332233362).
The spelling of 131212021231 in words is "one hundred thirty-one billion, two hundred twelve million, twenty-one thousand, two hundred thirty-one".
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