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131212023212441 is a prime number
BaseRepresentation
bin11101110101011000101110…
…000010001010100110011001
3122012120202011111111212120202
4131311120232002022212121
5114144234210420244231
61143021545445431545
736431520153060143
oct3565305602124631
9565522144455522
10131212023212441
113889878545a826
121287192910b5b5
13582a318a71082
1424589a5427c93
1510281d4a8c5cb
hex77562e08a999

131212023212441 has 2 divisors, whose sum is σ = 131212023212442. Its totient is φ = 131212023212440.

The previous prime is 131212023212437. The next prime is 131212023212461. The reversal of 131212023212441 is 144212320212131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114974064979216 + 16237958233225 = 10722596^2 + 4029635^2 .

It is a cyclic number.

It is not a de Polignac number, because 131212023212441 - 22 = 131212023212437 is a prime.

It is not a weakly prime, because it can be changed into another prime (131212023212461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606011606220 + 65606011606221.

It is an arithmetic number, because the mean of its divisors is an integer number (65606011606221).

Almost surely, 2131212023212441 is an apocalyptic number.

It is an amenable number.

131212023212441 is a deficient number, since it is larger than the sum of its proper divisors (1).

131212023212441 is an equidigital number, since it uses as much as digits as its factorization.

131212023212441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 131212023212441 its reverse (144212320212131), we get a palindrome (275424343424572).

The spelling of 131212023212441 in words is "one hundred thirty-one trillion, two hundred twelve billion, twenty-three million, two hundred twelve thousand, four hundred forty-one".