Base | Representation |
---|---|
bin | 1011111011110000010100… |
… | …0100101110000000110011 |
3 | 1201110101010200220022002112 |
4 | 2332330011010232000303 |
5 | 3204434214303244103 |
6 | 43523444544035535 |
7 | 2522655551405006 |
oct | 276740504560063 |
9 | 51411120808075 |
10 | 13121210212403 |
11 | 41a9746106357 |
12 | 157ab8a902bab |
13 | 74242b8013a7 |
14 | 3350d9d9953d |
15 | 17b4a59e3cd8 |
hex | bef0512e033 |
13121210212403 has 2 divisors, whose sum is σ = 13121210212404. Its totient is φ = 13121210212402.
The previous prime is 13121210212337. The next prime is 13121210212427. The reversal of 13121210212403 is 30421201212131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13121210212403 - 214 = 13121210196019 is a prime.
It is not a weakly prime, because it can be changed into another prime (13121210292403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560605106201 + 6560605106202.
It is an arithmetic number, because the mean of its divisors is an integer number (6560605106202).
Almost surely, 213121210212403 is an apocalyptic number.
13121210212403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121210212403 is an equidigital number, since it uses as much as digits as its factorization.
13121210212403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 13121210212403 its reverse (30421201212131), we get a palindrome (43542411424534).
The spelling of 13121210212403 in words is "thirteen trillion, one hundred twenty-one billion, two hundred ten million, two hundred twelve thousand, four hundred three".
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