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13121212023000 = 23325329463910837
BaseRepresentation
bin1011111011110000010100…
…1011101000000011011000
31201110101010211022021202200
42332330011023220003120
53204434220234214000
643523445050530200
72522655602655504
oct276740513500330
951411124267680
1013121212023000
1141a9747132714
12157ab8b436960
1374242bcb6553
143350da30b304
1517b4a5c50500
hexbef052e80d8

13121212023000 has 384 divisors, whose sum is σ = 45893120832000. Its totient is φ = 3377295129600.

The previous prime is 13121212022981. The next prime is 13121212023019. The reversal of 13121212023000 is 32021212131.

13121212023000 is a `hidden beast` number, since 1 + 31 + 212 + 120 + 2 + 300 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (13121212022981) and next prime (13121212023019).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1210773582 + ... + 1210784418.

It is an arithmetic number, because the mean of its divisors is an integer number (119513335500).

Almost surely, 213121212023000 is an apocalyptic number.

13121212023000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13121212023000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22946560416000).

13121212023000 is an abundant number, since it is smaller than the sum of its proper divisors (32771908809000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13121212023000 is a wasteful number, since it uses less digits than its factorization.

13121212023000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15532 (or 15515 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 13121212023000 its reverse (32021212131), we get a palindrome (13153233235131).

The spelling of 13121212023000 in words is "thirteen trillion, one hundred twenty-one billion, two hundred twelve million, twenty-three thousand".