Base | Representation |
---|---|
bin | 11101110101011000111000… |
… | …101100101001010010000011 |
3 | 122012120202121222011100001121 |
4 | 131311120320230221102003 |
5 | 114144240042220322243 |
6 | 1143022015320213111 |
7 | 36431524454546362 |
oct | 3565307054512203 |
9 | 565522558140047 |
10 | 131212202120323 |
11 | 38898867446985 |
12 | 1287197900a197 |
13 | 582a346b51b1c |
14 | 24589c10b97d9 |
15 | 10281e562c1ed |
hex | 775638b29483 |
131212202120323 has 2 divisors, whose sum is σ = 131212202120324. Its totient is φ = 131212202120322.
The previous prime is 131212202120317. The next prime is 131212202120359. The reversal of 131212202120323 is 323021202212131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131212202120323 - 29 = 131212202119811 is a prime.
It is not a weakly prime, because it can be changed into another prime (131212202120123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606101060161 + 65606101060162.
It is an arithmetic number, because the mean of its divisors is an integer number (65606101060162).
Almost surely, 2131212202120323 is an apocalyptic number.
131212202120323 is a deficient number, since it is larger than the sum of its proper divisors (1).
131212202120323 is an equidigital number, since it uses as much as digits as its factorization.
131212202120323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 131212202120323 its reverse (323021202212131), we get a palindrome (454233404332454).
The spelling of 131212202120323 in words is "one hundred thirty-one trillion, two hundred twelve billion, two hundred two million, one hundred twenty thousand, three hundred twenty-three".
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