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1312123011995 = 5262424602399
BaseRepresentation
bin10011000110000000101…
…000000100001110011011
311122102211002221021022102
4103012000220010032123
5132444211442340440
62442440405514015
7163540426402565
oct23060050041633
94572732837272
101312123011995
11466517262574
1219236b41290b
139696a89bb13
1447715668335
15241e8393b15
hex13180a0439b

1312123011995 has 4 divisors (see below), whose sum is σ = 1574547614400. Its totient is φ = 1049698409592.

The previous prime is 1312123011989. The next prime is 1312123012009. The reversal of 1312123011995 is 5991103212131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312123011995 - 214 = 1312122995611 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131212301195 + ... + 131212301204.

It is an arithmetic number, because the mean of its divisors is an integer number (393636903600).

Almost surely, 21312123011995 is an apocalyptic number.

1312123011995 is a deficient number, since it is larger than the sum of its proper divisors (262424602405).

1312123011995 is an equidigital number, since it uses as much as digits as its factorization.

1312123011995 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 262424602404.

The product of its (nonzero) digits is 14580, while the sum is 38.

The spelling of 1312123011995 in words is "one trillion, three hundred twelve billion, one hundred twenty-three million, eleven thousand, nine hundred ninety-five".

Divisors: 1 5 262424602399 1312123011995