131212443313141 has 4 divisors (see below), whose sum is σ = 133009874043532. Its totient is φ = 129415012582752.

The previous prime is 131212443313117. The next prime is 131212443313153. The reversal of 131212443313141 is 141313344212131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 112479811922500 + 18732631390641 = 10605650^2 + 4328121^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131212443313141 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131212443313097 and 131212443313106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131212443310141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 898715365086 + ... + 898715365231.

It is an arithmetic number, because the mean of its divisors is an integer number (33252468510883).

Almost surely, 2^{131212443313141} is an apocalyptic number.

It is an amenable number.

131212443313141 is a deficient number, since it is larger than the sum of its proper divisors (1797430730391).

131212443313141 is an equidigital number, since it uses as much as digits as its factorization.

131212443313141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1797430730390.

The product of its digits is 20736, while the sum is 34.

Adding to 131212443313141 its reverse (141313344212131), we get a palindrome (272525787525272).

The spelling of 131212443313141 in words is "one hundred thirty-one trillion, two hundred twelve billion, four hundred forty-three million, three hundred thirteen thousand, one hundred forty-one".