131212444101253 has 2 divisors, whose sum is σ = 131212444101254. Its totient is φ = 131212444101252.

The previous prime is 131212444101199. The next prime is 131212444101301. The reversal of 131212444101253 is 352101444212131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82637426603169 + 48575017498084 = 9090513^2 + 6969578^2 .

It is an emirp because it is prime and its reverse (352101444212131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131212444101253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131212444101553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606222050626 + 65606222050627.

It is an arithmetic number, because the mean of its divisors is an integer number (65606222050627).

Almost surely, 2^{131212444101253} is an apocalyptic number.

It is an amenable number.

131212444101253 is a deficient number, since it is larger than the sum of its proper divisors (1).

131212444101253 is an equidigital number, since it uses as much as digits as its factorization.

131212444101253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 34.

Adding to 131212444101253 its reverse (352101444212131), we get a palindrome (483313888313384).

The spelling of 131212444101253 in words is "one hundred thirty-one trillion, two hundred twelve billion, four hundred forty-four million, one hundred one thousand, two hundred fifty-three".