Base | Representation |
---|---|
bin | 11101110101011001101001… |
… | …000010101011000100110010 |
3 | 122012120211201111100111212011 |
4 | 131311121221002223010302 |
5 | 114144243222334414302 |
6 | 1143022232012353134 |
7 | 36431553533613562 |
oct | 3565315102530462 |
9 | 565524644314764 |
10 | 131213013201202 |
11 | 38899143265a59 |
12 | 12871b647757aa |
13 | 582a445bb453a |
14 | 2458a5aacada2 |
15 | 10282419425d7 |
hex | 7756690ab132 |
131213013201202 has 4 divisors (see below), whose sum is σ = 196819519801806. Its totient is φ = 65606506600600.
The previous prime is 131213013201139. The next prime is 131213013201241. The reversal of 131213013201202 is 202102310312131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 81369257881081 + 49843755320121 = 9020491^2 + 7060011^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32803253300299 + ... + 32803253300302.
Almost surely, 2131213013201202 is an apocalyptic number.
131213013201202 is a deficient number, since it is larger than the sum of its proper divisors (65606506600604).
131213013201202 is an equidigital number, since it uses as much as digits as its factorization.
131213013201202 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65606506600603.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 131213013201202 its reverse (202102310312131), we get a palindrome (333315323513333).
The spelling of 131213013201202 in words is "one hundred thirty-one trillion, two hundred thirteen billion, thirteen million, two hundred one thousand, two hundred two".
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