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131213103020204 = 2271462017968381
BaseRepresentation
bin11101110101011001101110…
…011001010011100010101100
3122012120211221202100210100212
4131311121232121103202230
5114144243413333121304
61143022244541441552
736431556004223552
oct3565315631234254
9565524852323325
10131213103020204
1138899189a33337
1212871b8a8702b8
13582a45b6a1c8a
142458a689cbbd2
15102824978566e
hex77566e6538ac

131213103020204 has 12 divisors (see below), whose sum is σ = 232857056064528. Its totient is φ = 64682515573200.

The previous prime is 131213103020161. The next prime is 131213103020261. The reversal of 131213103020204 is 402020301312131.

It is a self number, because there is not a number n which added to its sum of digits gives 131213103020204.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231008983907 + ... + 231008984474.

It is an arithmetic number, because the mean of its divisors is an integer number (19404754672044).

Almost surely, 2131213103020204 is an apocalyptic number.

It is an amenable number.

131213103020204 is a deficient number, since it is larger than the sum of its proper divisors (101643953044324).

131213103020204 is a wasteful number, since it uses less digits than its factorization.

131213103020204 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 462017968456 (or 462017968454 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 131213103020204 its reverse (402020301312131), we get a palindrome (533233404332335).

The spelling of 131213103020204 in words is "one hundred thirty-one trillion, two hundred thirteen billion, one hundred three million, twenty thousand, two hundred four".

Divisors: 1 2 4 71 142 284 462017968381 924035936762 1848071873524 32803275755051 65606551510102 131213103020204