13121312011333 has 4 divisors (see below), whose sum is σ = 13121968392288. Its totient is φ = 13120655630380.

The previous prime is 13121312011331. The next prime is 13121312011351. The reversal of 13121312011333 is 33311021312131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13121312011333 - 2¹ = 13121312011331 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13121312011298 and 13121312011307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13121312011331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 328160491 + ... + 328200472.

It is an arithmetic number, because the mean of its divisors is an integer number (3280492098072).

Almost surely, 2^{13121312011333} is an apocalyptic number.

It is an amenable number.

13121312011333 is a deficient number, since it is larger than the sum of its proper divisors (656380955).

13121312011333 is an equidigital number, since it uses as much as digits as its factorization.

13121312011333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 656380954.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 13121312011333 its reverse (33311021312131), we get a palindrome (46432333323464).

The spelling of 13121312011333 in words is "thirteen trillion, one hundred twenty-one billion, three hundred twelve million, eleven thousand, three hundred thirty-three".