Base | Representation |
---|---|
bin | 1011111011110000101100… |
… | …1001000110000111111010 |
3 | 1201110101101210110211000122 |
4 | 2332330023021012013322 |
5 | 3204434421334214114 |
6 | 43523503022133242 |
7 | 2522661225651005 |
oct | 276741311060772 |
9 | 51411353424018 |
10 | 13121312023034 |
11 | 41a9798624176 |
12 | 157abb8a21222 |
13 | 74244692a077 |
14 | 3351096dc53c |
15 | 17b4ae904e8e |
hex | bef0b2461fa |
13121312023034 has 4 divisors (see below), whose sum is σ = 19681968034554. Its totient is φ = 6560656011516.
The previous prime is 13121312022983. The next prime is 13121312023073. The reversal of 13121312023034 is 43032021312131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13118862268009 + 2449755025 = 3621997^2 + 49495^2 .
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13121312022994 and 13121312023012.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3280328005757 + ... + 3280328005760.
Almost surely, 213121312023034 is an apocalyptic number.
13121312023034 is a deficient number, since it is larger than the sum of its proper divisors (6560656011520).
13121312023034 is an equidigital number, since it uses as much as digits as its factorization.
13121312023034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6560656011519.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 13121312023034 its reverse (43032021312131), we get a palindrome (56153333335165).
The spelling of 13121312023034 in words is "thirteen trillion, one hundred twenty-one billion, three hundred twelve million, twenty-three thousand, thirty-four".
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