Base | Representation |
---|---|
bin | 111101000110011101… |
… | …0101000111011101011 |
3 | 110112200110210020201001 |
4 | 1322030322220323223 |
5 | 4122211034414011 |
6 | 140140054135431 |
7 | 12323404543615 |
oct | 1721472507353 |
9 | 415613706631 |
10 | 131213201131 |
11 | 507134820a1 |
12 | 2151b051577 |
13 | c4b133b91c |
14 | 64ca673db5 |
15 | 362e60a7c1 |
hex | 1e8cea8eeb |
131213201131 has 4 divisors (see below), whose sum is σ = 131226487672. Its totient is φ = 131199914592.
The previous prime is 131213201071. The next prime is 131213201137. The reversal of 131213201131 is 131102312131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131213201131 - 211 = 131213199083 is a prime.
It is a super-2 number, since 2×1312132011312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131213201099 and 131213201108.
It is not an unprimeable number, because it can be changed into a prime (131213201137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6628446 + ... + 6648211.
It is an arithmetic number, because the mean of its divisors is an integer number (32806621918).
Almost surely, 2131213201131 is an apocalyptic number.
131213201131 is a deficient number, since it is larger than the sum of its proper divisors (13286541).
131213201131 is an equidigital number, since it uses as much as digits as its factorization.
131213201131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13286540.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 131213201131 its reverse (131102312131), we get a palindrome (262315513262).
The spelling of 131213201131 in words is "one hundred thirty-one billion, two hundred thirteen million, two hundred one thousand, one hundred thirty-one".
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