Base | Representation |
---|---|
bin | 1011111011110000110001… |
… | …1010010101100101000011 |
3 | 1201110101110021112210222021 |
4 | 2332330030122111211003 |
5 | 3204434442312220003 |
6 | 43523505102422311 |
7 | 2522661604661206 |
oct | 276741432254503 |
9 | 51411407483867 |
10 | 13121333320003 |
11 | 41a97a964a977 |
12 | 157b003b91997 |
13 | 74244b17591c |
14 | 33510c48393d |
15 | 17b4b17102bd |
hex | bef0c695943 |
13121333320003 has 2 divisors, whose sum is σ = 13121333320004. Its totient is φ = 13121333320002.
The previous prime is 13121333319977. The next prime is 13121333320049. The reversal of 13121333320003 is 30002333312131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13121333320003 - 25 = 13121333319971 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13121333320003.
It is not a weakly prime, because it can be changed into another prime (13121333350003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560666660001 + 6560666660002.
It is an arithmetic number, because the mean of its divisors is an integer number (6560666660002).
Almost surely, 213121333320003 is an apocalyptic number.
13121333320003 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121333320003 is an equidigital number, since it uses as much as digits as its factorization.
13121333320003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 13121333320003 its reverse (30002333312131), we get a palindrome (43123666632134).
The spelling of 13121333320003 in words is "thirteen trillion, one hundred twenty-one billion, three hundred thirty-three million, three hundred twenty thousand, three".
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