13121401403041 has 2 divisors, whose sum is σ = 13121401403042. Its totient is φ = 13121401403040.

The previous prime is 13121401403039. The next prime is 13121401403053. The reversal of 13121401403041 is 14030410412131.

13121401403041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12460928240016 + 660473163025 = 3530004^2 + 812695^2 .

It is a cyclic number.

It is not a de Polignac number, because 13121401403041 - 2¹ = 13121401403039 is a prime.

Together with 13121401403039, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13121401402997 and 13121401403015.

It is not a weakly prime, because it can be changed into another prime (13121401406041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560700701520 + 6560700701521.

It is an arithmetic number, because the mean of its divisors is an integer number (6560700701521).

Almost surely, 2^{13121401403041} is an apocalyptic number.

It is an amenable number.

13121401403041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121401403041 is an equidigital number, since it uses as much as digits as its factorization.

13121401403041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13121401403041 its reverse (14030410412131), we get a palindrome (27151811815172).

The spelling of 13121401403041 in words is "thirteen trillion, one hundred twenty-one billion, four hundred one million, four hundred three thousand, forty-one".