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13121404027327 is a prime number
BaseRepresentation
bin1011111011110001000010…
…1000000100000110111111
31201110101122012121010012001
42332330100220010012333
53204440113412333302
643523520110123131
72522663423662051
oct276742050040677
951411565533161
1013121404027327
1141a9835554382
12157b0237b04a7
1374245ca0138b
14335117a0b8d1
1517b4b7a2a787
hexbef10a041bf

13121404027327 has 2 divisors, whose sum is σ = 13121404027328. Its totient is φ = 13121404027326.

The previous prime is 13121404027307. The next prime is 13121404027337. The reversal of 13121404027327 is 72372040412131.

13121404027327 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13121404027327 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13121404027307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560702013663 + 6560702013664.

It is an arithmetic number, because the mean of its divisors is an integer number (6560702013664).

Almost surely, 213121404027327 is an apocalyptic number.

13121404027327 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121404027327 is an equidigital number, since it uses as much as digits as its factorization.

13121404027327 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56448, while the sum is 37.

Adding to 13121404027327 its reverse (72372040412131), we get a palindrome (85493444439458).

The spelling of 13121404027327 in words is "thirteen trillion, one hundred twenty-one billion, four hundred four million, twenty-seven thousand, three hundred twenty-seven".