Base | Representation |
---|---|
bin | 11101110101011010100110… |
… | …010011110101110110110011 |
3 | 122012120221101010112210100222 |
4 | 131311122212103311312303 |
5 | 114144302324011040422 |
6 | 1143022522012203255 |
7 | 36431621154662201 |
oct | 3565324623656663 |
9 | 565527333483328 |
10 | 131214041111987 |
11 | 388996205125a9 |
12 | 128721b0a6952b |
13 | 582a57ab44782 |
14 | 2458b17422071 |
15 | 10282a1cd8842 |
hex | 7756a64f5db3 |
131214041111987 has 2 divisors, whose sum is σ = 131214041111988. Its totient is φ = 131214041111986.
The previous prime is 131214041111957. The next prime is 131214041112043. The reversal of 131214041111987 is 789111140412131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131214041111987 - 28 = 131214041111731 is a prime.
It is not a weakly prime, because it can be changed into another prime (131214041111957) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65607020555993 + 65607020555994.
It is an arithmetic number, because the mean of its divisors is an integer number (65607020555994).
Almost surely, 2131214041111987 is an apocalyptic number.
131214041111987 is a deficient number, since it is larger than the sum of its proper divisors (1).
131214041111987 is an equidigital number, since it uses as much as digits as its factorization.
131214041111987 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 44.
The spelling of 131214041111987 in words is "one hundred thirty-one trillion, two hundred fourteen billion, forty-one million, one hundred eleven thousand, nine hundred eighty-seven".
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