Base | Representation |
---|---|
bin | 11101110101011010100110… |
… | …010011110101110111101011 |
3 | 122012120221101010112210110001 |
4 | 131311122212103311313223 |
5 | 114144302324011041133 |
6 | 1143022522012203431 |
7 | 36431621154662311 |
oct | 3565324623656753 |
9 | 565527333483401 |
10 | 131214041112043 |
11 | 3889962051264a |
12 | 128721b0a69577 |
13 | 582a57ab447c6 |
14 | 2458b174220b1 |
15 | 10282a1cd887d |
hex | 7756a64f5deb |
131214041112043 has 2 divisors, whose sum is σ = 131214041112044. Its totient is φ = 131214041112042.
The previous prime is 131214041111987. The next prime is 131214041112061. The reversal of 131214041112043 is 340211140412131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131214041112043 - 213 = 131214041103851 is a prime.
It is not a weakly prime, because it can be changed into another prime (131214041112743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65607020556021 + 65607020556022.
It is an arithmetic number, because the mean of its divisors is an integer number (65607020556022).
Almost surely, 2131214041112043 is an apocalyptic number.
131214041112043 is a deficient number, since it is larger than the sum of its proper divisors (1).
131214041112043 is an equidigital number, since it uses as much as digits as its factorization.
131214041112043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 131214041112043 its reverse (340211140412131), we get a palindrome (471425181524174).
The spelling of 131214041112043 in words is "one hundred thirty-one trillion, two hundred fourteen billion, forty-one million, one hundred twelve thousand, forty-three".
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