Base | Representation |
---|---|
bin | 10011000110000001101… |
… | …010011111001110110011 |
3 | 11122102212022200220020202 |
4 | 103012001222133032303 |
5 | 132444230422032430 |
6 | 2442442231025415 |
7 | 163541030403023 |
oct | 23060152371663 |
9 | 4572768626222 |
10 | 1312140424115 |
11 | 466526075554 |
12 | 19237520b26b |
13 | 96971387351 |
14 | 47717abba83 |
15 | 241e9b82d45 |
hex | 13181a9f3b3 |
1312140424115 has 4 divisors (see below), whose sum is σ = 1574568508944. Its totient is φ = 1049712339288.
The previous prime is 1312140424081. The next prime is 1312140424121. The reversal of 1312140424115 is 5114240412131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1312140424115 - 216 = 1312140358579 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131214042407 + ... + 131214042416.
It is an arithmetic number, because the mean of its divisors is an integer number (393642127236).
Almost surely, 21312140424115 is an apocalyptic number.
1312140424115 is a deficient number, since it is larger than the sum of its proper divisors (262428084829).
1312140424115 is an equidigital number, since it uses as much as digits as its factorization.
1312140424115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 262428084828.
The product of its (nonzero) digits is 3840, while the sum is 29.
Adding to 1312140424115 its reverse (5114240412131), we get a palindrome (6426380836246).
The spelling of 1312140424115 in words is "one trillion, three hundred twelve billion, one hundred forty million, four hundred twenty-four thousand, one hundred fifteen".
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