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1312140424115 = 5262428084823
BaseRepresentation
bin10011000110000001101…
…010011111001110110011
311122102212022200220020202
4103012001222133032303
5132444230422032430
62442442231025415
7163541030403023
oct23060152371663
94572768626222
101312140424115
11466526075554
1219237520b26b
1396971387351
1447717abba83
15241e9b82d45
hex13181a9f3b3

1312140424115 has 4 divisors (see below), whose sum is σ = 1574568508944. Its totient is φ = 1049712339288.

The previous prime is 1312140424081. The next prime is 1312140424121. The reversal of 1312140424115 is 5114240412131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312140424115 - 216 = 1312140358579 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131214042407 + ... + 131214042416.

It is an arithmetic number, because the mean of its divisors is an integer number (393642127236).

Almost surely, 21312140424115 is an apocalyptic number.

1312140424115 is a deficient number, since it is larger than the sum of its proper divisors (262428084829).

1312140424115 is an equidigital number, since it uses as much as digits as its factorization.

1312140424115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 262428084828.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 1312140424115 its reverse (5114240412131), we get a palindrome (6426380836246).

The spelling of 1312140424115 in words is "one trillion, three hundred twelve billion, one hundred forty million, four hundred twenty-four thousand, one hundred fifteen".

Divisors: 1 5 262428084823 1312140424115