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13121410004467 is a prime number
BaseRepresentation
bin1011111011110001000011…
…1110110111010111110011
31201110101122121211210021121
42332330100332313113303
53204440121430120332
643523520442203111
72522663525535112
oct276742076672763
951411577753247
1013121410004467
1141a9838967066
12157b0257b3497
13742461014b4b
14335118725c79
1517b4b830b797
hexbef10fb75f3

13121410004467 has 2 divisors, whose sum is σ = 13121410004468. Its totient is φ = 13121410004466.

The previous prime is 13121410004401. The next prime is 13121410004489. The reversal of 13121410004467 is 76440001412131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13121410004467 is a prime.

It is not a weakly prime, because it can be changed into another prime (13121410004567) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560705002233 + 6560705002234.

It is an arithmetic number, because the mean of its divisors is an integer number (6560705002234).

Almost surely, 213121410004467 is an apocalyptic number.

13121410004467 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121410004467 is an equidigital number, since it uses as much as digits as its factorization.

13121410004467 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 34.

Adding to 13121410004467 its reverse (76440001412131), we get a palindrome (89561411416598).

The spelling of 13121410004467 in words is "thirteen trillion, one hundred twenty-one billion, four hundred ten million, four thousand, four hundred sixty-seven".