Base | Representation |
---|---|
bin | 10011000110000001101… |
… | …100101111000010000001 |
3 | 11122102212100210211012210 |
4 | 103012001230233002001 |
5 | 132444231044404441 |
6 | 2442442251412333 |
7 | 163541035405161 |
oct | 23060154570201 |
9 | 4572770724183 |
10 | 1312141013121 |
11 | 466526438034 |
12 | 1923754540a9 |
13 | 96971532483 |
14 | 47717bd25a1 |
15 | 241e9c4c616 |
hex | 13181b2f081 |
1312141013121 has 4 divisors (see below), whose sum is σ = 1749521350832. Its totient is φ = 874760675412.
The previous prime is 1312141013119. The next prime is 1312141013153. The reversal of 1312141013121 is 1213101412131.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1312141013121 - 21 = 1312141013119 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1312141013101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218690168851 + ... + 218690168856.
It is an arithmetic number, because the mean of its divisors is an integer number (437380337708).
Almost surely, 21312141013121 is an apocalyptic number.
It is an amenable number.
1312141013121 is a deficient number, since it is larger than the sum of its proper divisors (437380337711).
1312141013121 is an equidigital number, since it uses as much as digits as its factorization.
1312141013121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 437380337710.
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 1312141013121 its reverse (1213101412131), we get a palindrome (2525242425252).
The spelling of 1312141013121 in words is "one trillion, three hundred twelve billion, one hundred forty-one million, thirteen thousand, one hundred twenty-one".
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