Base | Representation |
---|---|
bin | 1011111011110001001000… |
… | …1111011000111001101011 |
3 | 1201110101201002120020012002 |
4 | 2332330102033120321223 |
5 | 3204440142331111243 |
6 | 43523522514441215 |
7 | 2522664203133011 |
oct | 276742217307153 |
9 | 51411632506162 |
10 | 13121431113323 |
11 | 41a98498744a5 |
12 | 157b03089320b |
13 | 7424654c5bb0 |
14 | 33511b45c8b1 |
15 | 17b4ba0caeb8 |
hex | bef123d8e6b |
13121431113323 has 16 divisors (see below), whose sum is σ = 15326920538496. Its totient is φ = 11121574978560.
The previous prime is 13121431113251. The next prime is 13121431113379. The reversal of 13121431113323 is 32331113412131.
It is a cyclic number.
It is not a de Polignac number, because 13121431113323 - 210 = 13121431112299 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13121431113223) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 724051811 + ... + 724069932.
It is an arithmetic number, because the mean of its divisors is an integer number (957932533656).
Almost surely, 213121431113323 is an apocalyptic number.
13121431113323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13121431113323 is a deficient number, since it is larger than the sum of its proper divisors (2205489425173).
13121431113323 is a wasteful number, since it uses less digits than its factorization.
13121431113323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1448121814.
The product of its digits is 3888, while the sum is 29.
Adding to 13121431113323 its reverse (32331113412131), we get a palindrome (45452544525454).
The spelling of 13121431113323 in words is "thirteen trillion, one hundred twenty-one billion, four hundred thirty-one million, one hundred thirteen thousand, three hundred twenty-three".
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