13121434984639 has 2 divisors, whose sum is σ = 13121434984640. Its totient is φ = 13121434984638.

The previous prime is 13121434984547. The next prime is 13121434984663. The reversal of 13121434984639 is 93648943412131.

It is a strong prime.

It is an emirp because it is prime and its reverse (93648943412131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13121434984639 is a prime.

It is a super-3 number, since 3×13121434984639³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13121434984739) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560717492319 + 6560717492320.

It is an arithmetic number, because the mean of its divisors is an integer number (6560717492320).

Almost surely, 2^{13121434984639} is an apocalyptic number.

13121434984639 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121434984639 is an equidigital number, since it uses as much as digits as its factorization.

13121434984639 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13436928, while the sum is 58.

The spelling of 13121434984639 in words is "thirteen trillion, one hundred twenty-one billion, four hundred thirty-four million, nine hundred eighty-four thousand, six hundred thirty-nine".