Base | Representation |
---|---|
bin | 11101110101011010111101… |
… | …001010000000111111100011 |
3 | 122012120222100211210110022121 |
4 | 131311122331022000333203 |
5 | 114144304120122142011 |
6 | 1143023024023445111 |
7 | 36431633520661264 |
oct | 3565327512007743 |
9 | 565528324713277 |
10 | 131214424412131 |
11 | 388997a7911685 |
12 | 128722992b6797 |
13 | 582a60c389aa8 |
14 | 2458b522ba96b |
15 | 10282c579de71 |
hex | 7756bd280fe3 |
131214424412131 has 4 divisors (see below), whose sum is σ = 131214609258712. Its totient is φ = 131214239565552.
The previous prime is 131214424412117. The next prime is 131214424412147.
It is a happy number.
131214424412131 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131214424412131 is a prime.
It is a super-2 number, since 2×1312144244121312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131214424412111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91354386 + ... + 92779591.
It is an arithmetic number, because the mean of its divisors is an integer number (32803652314678).
Almost surely, 2131214424412131 is an apocalyptic number.
131214424412131 is a deficient number, since it is larger than the sum of its proper divisors (184846581).
131214424412131 is an equidigital number, since it uses as much as digits as its factorization.
131214424412131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 184846580.
The product of its digits is 18432, while the sum is 34.
The spelling of 131214424412131 in words is "one hundred thirty-one trillion, two hundred fourteen billion, four hundred twenty-four million, four hundred twelve thousand, one hundred thirty-one".
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