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131214439 is a prime number
BaseRepresentation
bin1111101001000…
…10110001100111
3100010220101101001
413310202301213
5232042330224
621004214131
73152206246
oct764426147
9303811331
10131214439
1168081394
1237b3a347
13212524a5
14135d895d
15b7bd544
hex7d22c67

131214439 has 2 divisors, whose sum is σ = 131214440. Its totient is φ = 131214438.

The previous prime is 131214427. The next prime is 131214443. The reversal of 131214439 is 934412131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131214439 - 213 = 131206247 is a prime.

It is a Chen prime.

It is equal to p7443181 and since 131214439 and 7443181 have the same sum of digits, it is a Honaker prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131214409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65607219 + 65607220.

It is an arithmetic number, because the mean of its divisors is an integer number (65607220).

Almost surely, 2131214439 is an apocalyptic number.

131214439 is a deficient number, since it is larger than the sum of its proper divisors (1).

131214439 is an equidigital number, since it uses as much as digits as its factorization.

131214439 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2592, while the sum is 28.

The square root of 131214439 is about 11454.8871229707. The cubic root of 131214439 is about 508.1522770288.

It can be divided in two parts, 1312 and 14439, that added together give a palindrome (15751).

The spelling of 131214439 in words is "one hundred thirty-one million, two hundred fourteen thousand, four hundred thirty-nine".