Base | Representation |
---|---|
bin | 1011111011110001001100… |
… | …0000100110000101010011 |
3 | 1201110101201222211120100121 |
4 | 2332330103000212011103 |
5 | 3204440204131343441 |
6 | 43523524055131111 |
7 | 2522664420565402 |
oct | 276742300460523 |
9 | 51411658746317 |
10 | 13121444012371 |
11 | 41a9856084772 |
12 | 157b035073a97 |
13 | 742468091176 |
14 | 33511d059639 |
15 | 17b4bb2c7dd1 |
hex | bef13026153 |
13121444012371 has 2 divisors, whose sum is σ = 13121444012372. Its totient is φ = 13121444012370.
The previous prime is 13121444012359. The next prime is 13121444012389. The reversal of 13121444012371 is 17321044412131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13121444012371 is a prime.
It is not a weakly prime, because it can be changed into another prime (13121444012321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560722006185 + 6560722006186.
It is an arithmetic number, because the mean of its divisors is an integer number (6560722006186).
Almost surely, 213121444012371 is an apocalyptic number.
13121444012371 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121444012371 is an equidigital number, since it uses as much as digits as its factorization.
13121444012371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 34.
The spelling of 13121444012371 in words is "thirteen trillion, one hundred twenty-one billion, four hundred forty-four million, twelve thousand, three hundred seventy-one".
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