Base | Representation |
---|---|
bin | 111101000110101010… |
… | …0101001111110001101 |
3 | 110112200221121201222201 |
4 | 1322031110221332031 |
5 | 4122214311134013 |
6 | 140140500241501 |
7 | 12323516530165 |
oct | 1721524517615 |
9 | 415627551881 |
10 | 131220021133 |
11 | 50717310063 |
12 | 215213a0291 |
13 | c4b2888c26 |
14 | 64cb52b5a5 |
15 | 36300063dd |
hex | 1e8d529f8d |
131220021133 has 4 divisors (see below), whose sum is σ = 131220750240. Its totient is φ = 131219292028.
The previous prime is 131220021103. The next prime is 131220021137. The reversal of 131220021133 is 331120022131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 331120022131 = 83 ⋅3989397857.
It is a cyclic number.
It is not a de Polignac number, because 131220021133 - 233 = 122630086541 is a prime.
It is a super-2 number, since 2×1312200211332 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 131220021133.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131220021137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120816 + ... + 526342.
It is an arithmetic number, because the mean of its divisors is an integer number (32805187560).
Almost surely, 2131220021133 is an apocalyptic number.
It is an amenable number.
131220021133 is a deficient number, since it is larger than the sum of its proper divisors (729107).
131220021133 is an equidigital number, since it uses as much as digits as its factorization.
131220021133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 729106.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 131220021133 its reverse (331120022131), we get a palindrome (462340043264).
The spelling of 131220021133 in words is "one hundred thirty-one billion, two hundred twenty million, twenty-one thousand, one hundred thirty-three".
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