Base | Representation |
---|---|
bin | 111101000110101010… |
… | …0111101101111011011 |
3 | 110112200221202212001202 |
4 | 1322031110331233123 |
5 | 4122214321231412 |
6 | 140140502104415 |
7 | 12323520315233 |
oct | 1721524755733 |
9 | 415627685052 |
10 | 131220102107 |
11 | 50717365986 |
12 | 2152141b10b |
13 | c4b28b6a43 |
14 | 64cb54ccc3 |
15 | 36300203c2 |
hex | 1e8d53dbdb |
131220102107 has 2 divisors, whose sum is σ = 131220102108. Its totient is φ = 131220102106.
The previous prime is 131220102053. The next prime is 131220102109. The reversal of 131220102107 is 701201022131.
It is a strong prime.
It is an emirp because it is prime and its reverse (701201022131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131220102107 - 28 = 131220101851 is a prime.
Together with 131220102109, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (131220102109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65610051053 + 65610051054.
It is an arithmetic number, because the mean of its divisors is an integer number (65610051054).
Almost surely, 2131220102107 is an apocalyptic number.
131220102107 is a deficient number, since it is larger than the sum of its proper divisors (1).
131220102107 is an equidigital number, since it uses as much as digits as its factorization.
131220102107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 20.
Adding to 131220102107 its reverse (701201022131), we get a palindrome (832421124238).
The spelling of 131220102107 in words is "one hundred thirty-one billion, two hundred twenty million, one hundred two thousand, one hundred seven".
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