Base | Representation |
---|---|
bin | 11000011100010001… |
… | …00000100000100001 |
3 | 1020212111101100010112 |
4 | 30032020200200201 |
5 | 203333213410332 |
6 | 10010030141105 |
7 | 643114162205 |
oct | 141610404041 |
9 | 36774340115 |
10 | 13122013217 |
11 | 5624041825 |
12 | 2662651795 |
13 | 1311752081 |
14 | 8c6a4ab05 |
15 | 51c003db2 |
hex | 30e220821 |
13122013217 has 2 divisors, whose sum is σ = 13122013218. Its totient is φ = 13122013216.
The previous prime is 13122013189. The next prime is 13122013241. The reversal of 13122013217 is 71231022131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7894144801 + 5227868416 = 88849^2 + 72304^2 .
It is an emirp because it is prime and its reverse (71231022131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13122013217 - 216 = 13121947681 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13122013192 and 13122013201.
It is not a weakly prime, because it can be changed into another prime (13122013297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561006608 + 6561006609.
It is an arithmetic number, because the mean of its divisors is an integer number (6561006609).
Almost surely, 213122013217 is an apocalyptic number.
It is an amenable number.
13122013217 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122013217 is an equidigital number, since it uses as much as digits as its factorization.
13122013217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 13122013217 its reverse (71231022131), we get a palindrome (84353035348).
The spelling of 13122013217 in words is "thirteen billion, one hundred twenty-two million, thirteen thousand, two hundred seventeen".
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