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1312201330001 = 1583828933247
BaseRepresentation
bin10011000110000101010…
…010110100110101010001
311122110000120022020102022
4103012011102310311101
5132444342020030001
62442452244301225
7163542400162142
oct23060522646521
94573016266368
101312201330001
11466557494aa1
121923916a1815
1396980b90733
1447721c13ac9
15242001b411b
hex131854b4d51

1312201330001 has 4 divisors (see below), whose sum is σ = 1313030264832. Its totient is φ = 1311372395172.

The previous prime is 1312201329953. The next prime is 1312201330021. The reversal of 1312201330001 is 1000331022131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1312201330001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1312201330021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 414465041 + ... + 414468206.

It is an arithmetic number, because the mean of its divisors is an integer number (328257566208).

Almost surely, 21312201330001 is an apocalyptic number.

It is an amenable number.

1312201330001 is a deficient number, since it is larger than the sum of its proper divisors (828934831).

1312201330001 is an equidigital number, since it uses as much as digits as its factorization.

1312201330001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 828934830.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1312201330001 its reverse (1000331022131), we get a palindrome (2312532352132).

The spelling of 1312201330001 in words is "one trillion, three hundred twelve billion, two hundred one million, three hundred thirty thousand, one".

Divisors: 1 1583 828933247 1312201330001