Base | Representation |
---|---|
bin | 10011000110000101110… |
… | …011111110101100001011 |
3 | 11122110001011122210102000 |
4 | 103012011303332230023 |
5 | 132444401231134011 |
6 | 2442453154442043 |
7 | 163542534100542 |
oct | 23060563765413 |
9 | 4573034583360 |
10 | 1312210021131 |
11 | 466561390849 |
12 | 192394593323 |
13 | 96982914609 |
14 | 47723037159 |
15 | 24200d2e356 |
hex | 13185cfeb0b |
1312210021131 has 8 divisors (see below), whose sum is σ = 1944014846160. Its totient is φ = 874806680736.
The previous prime is 1312210021081. The next prime is 1312210021181. The reversal of 1312210021131 is 1311200122131.
It is an interprime number because it is at equal distance from previous prime (1312210021081) and next prime (1312210021181).
It is not a de Polignac number, because 1312210021131 - 218 = 1312209758987 is a prime.
It is a super-2 number, since 2×13122100211312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1312210021181) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24300185550 + ... + 24300185603.
It is an arithmetic number, because the mean of its divisors is an integer number (243001855770).
Almost surely, 21312210021131 is an apocalyptic number.
1312210021131 is a deficient number, since it is larger than the sum of its proper divisors (631804825029).
1312210021131 is an equidigital number, since it uses as much as digits as its factorization.
1312210021131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48600371162 (or 48600371156 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 1312210021131 its reverse (1311200122131), we get a palindrome (2623410143262).
The spelling of 1312210021131 in words is "one trillion, three hundred twelve billion, two hundred ten million, twenty-one thousand, one hundred thirty-one".
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