Base | Representation |
---|---|
bin | 1011111011110011101000… |
… | …1111111000111001110111 |
3 | 1201110110102212120201112212 |
4 | 2332330322033320321313 |
5 | 3204443031144124142 |
6 | 43524113253204035 |
7 | 2523016633325561 |
oct | 276747217707167 |
9 | 51413385521485 |
10 | 13122102333047 |
11 | 41aa063746844 |
12 | 157b19963061b |
13 | 742541599526 |
14 | 335182664331 |
15 | 17b508eb5d82 |
hex | bef3a3f8e77 |
13122102333047 has 2 divisors, whose sum is σ = 13122102333048. Its totient is φ = 13122102333046.
The previous prime is 13122102333007. The next prime is 13122102333089. The reversal of 13122102333047 is 74033320122131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13122102333047 - 28 = 13122102332791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13122102333007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561051166523 + 6561051166524.
It is an arithmetic number, because the mean of its divisors is an integer number (6561051166524).
Almost surely, 213122102333047 is an apocalyptic number.
13122102333047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122102333047 is an equidigital number, since it uses as much as digits as its factorization.
13122102333047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 32.
Adding to 13122102333047 its reverse (74033320122131), we get a palindrome (87155422455178).
The spelling of 13122102333047 in words is "thirteen trillion, one hundred twenty-two billion, one hundred two million, three hundred thirty-three thousand, forty-seven".
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