Base | Representation |
---|---|
bin | 10011000110000101110… |
… | …101000111101111011011 |
3 | 11122110001012012222212002 |
4 | 103012011311013233123 |
5 | 132444401320222342 |
6 | 2442453205111215 |
7 | 163542536455103 |
oct | 23060565075733 |
9 | 4573035188762 |
10 | 1312210320347 |
11 | 466561575633 |
12 | 1923946b850b |
13 | 969829ba874 |
14 | 477230b4203 |
15 | 24200d8cd32 |
hex | 13185d47bdb |
1312210320347 has 2 divisors, whose sum is σ = 1312210320348. Its totient is φ = 1312210320346.
The previous prime is 1312210320319. The next prime is 1312210320353. The reversal of 1312210320347 is 7430230122131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1312210320347 - 212 = 1312210316251 is a prime.
It is not a weakly prime, because it can be changed into another prime (1312210325347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656105160173 + 656105160174.
It is an arithmetic number, because the mean of its divisors is an integer number (656105160174).
Almost surely, 21312210320347 is an apocalyptic number.
1312210320347 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312210320347 is an equidigital number, since it uses as much as digits as its factorization.
1312210320347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 1312210320347 its reverse (7430230122131), we get a palindrome (8742440442478).
The spelling of 1312210320347 in words is "one trillion, three hundred twelve billion, two hundred ten million, three hundred twenty thousand, three hundred forty-seven".
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