Base | Representation |
---|---|
bin | 10011000110000101110… |
… | …101100101001110010111 |
3 | 11122110001012110010111211 |
4 | 103012011311211032113 |
5 | 132444401333103421 |
6 | 2442453211442251 |
7 | 163542540500143 |
oct | 23060565451627 |
9 | 4573035403454 |
10 | 1312210441111 |
11 | 466561648339 |
12 | 192394756387 |
13 | 96982a3081b |
14 | 47723106223 |
15 | 24200db39e1 |
hex | 13185d65397 |
1312210441111 has 2 divisors, whose sum is σ = 1312210441112. Its totient is φ = 1312210441110.
The previous prime is 1312210441067. The next prime is 1312210441127. The reversal of 1312210441111 is 1111440122131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1312210441111 - 211 = 1312210439063 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312210441411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656105220555 + 656105220556.
It is an arithmetic number, because the mean of its divisors is an integer number (656105220556).
Almost surely, 21312210441111 is an apocalyptic number.
1312210441111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312210441111 is an equidigital number, since it uses as much as digits as its factorization.
1312210441111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 22.
Adding to 1312210441111 its reverse (1111440122131), we get a palindrome (2423650563242).
The spelling of 1312210441111 in words is "one trillion, three hundred twelve billion, two hundred ten million, four hundred forty-one thousand, one hundred eleven".
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