Base | Representation |
---|---|
bin | 1011111011110011101101… |
… | …1000110010010010000010 |
3 | 1201110110111012112120200221 |
4 | 2332330323120302102002 |
5 | 3204443101042124214 |
6 | 43524115214533254 |
7 | 2523020254625224 |
oct | 276747330622202 |
9 | 51413435476627 |
10 | 13122121442434 |
11 | 41aa073508a24 |
12 | 157b1a3b0722a |
13 | 74254552a464 |
14 | 335184dda414 |
15 | 17b50a9dce24 |
hex | bef3b632482 |
13122121442434 has 4 divisors (see below), whose sum is σ = 19683182163654. Its totient is φ = 6561060721216.
The previous prime is 13122121442429. The next prime is 13122121442447. The reversal of 13122121442434 is 43424412122131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11683045294209 + 1439076148225 = 3418047^2 + 1199615^2 .
It is a super-2 number, since 2×131221214424342 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13122121442434.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3280530360607 + ... + 3280530360610.
Almost surely, 213122121442434 is an apocalyptic number.
13122121442434 is a deficient number, since it is larger than the sum of its proper divisors (6561060721220).
13122121442434 is an equidigital number, since it uses as much as digits as its factorization.
13122121442434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6561060721219.
The product of its digits is 36864, while the sum is 34.
Adding to 13122121442434 its reverse (43424412122131), we get a palindrome (56546533564565).
The spelling of 13122121442434 in words is "thirteen trillion, one hundred twenty-two billion, one hundred twenty-one million, four hundred forty-two thousand, four hundred thirty-four".
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