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131221240412231 is a prime number
BaseRepresentation
bin11101110101100001010011…
…011010111111100001000111
3122012121121221212022010200202
4131311201103122333201013
5114144412100021142411
61143030112230201115
736432264444012554
oct3565412332774107
9565547855263622
10131221240412231
11388a1685311412
121287367bab319b
13582b15751b348
1424591db61ba2b
151028573d6e83b
hex7758536bf847

131221240412231 has 2 divisors, whose sum is σ = 131221240412232. Its totient is φ = 131221240412230.

The previous prime is 131221240412117. The next prime is 131221240412237. The reversal of 131221240412231 is 132214042122131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131221240412231 - 222 = 131221236217927 is a prime.

It is a super-2 number, since 2×1312212404122312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131221240412194 and 131221240412203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131221240412237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65610620206115 + 65610620206116.

It is an arithmetic number, because the mean of its divisors is an integer number (65610620206116).

Almost surely, 2131221240412231 is an apocalyptic number.

131221240412231 is a deficient number, since it is larger than the sum of its proper divisors (1).

131221240412231 is an equidigital number, since it uses as much as digits as its factorization.

131221240412231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 131221240412231 its reverse (132214042122131), we get a palindrome (263435282534362).

The spelling of 131221240412231 in words is "one hundred thirty-one trillion, two hundred twenty-one billion, two hundred forty million, four hundred twelve thousand, two hundred thirty-one".