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131221312102 = 265610656051
BaseRepresentation
bin111101000110101100…
…1100101001001100110
3110112201001001022212101
41322031121211021212
54122220123441402
6140140544042314
712323533515016
oct1721531451146
9415631038771
10131221312102
1150718011a81
122152190339a
13c4b2c1b70a
1464cb785c46
1536301adb87
hex1e8d665266

131221312102 has 4 divisors (see below), whose sum is σ = 196831968156. Its totient is φ = 65610656050.

The previous prime is 131221312073. The next prime is 131221312127. The reversal of 131221312102 is 201213122131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 201213122131 = 728744731733.

It is a self number, because there is not a number n which added to its sum of digits gives 131221312102.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32805328024 + ... + 32805328027.

It is an arithmetic number, because the mean of its divisors is an integer number (49207992039).

Almost surely, 2131221312102 is an apocalyptic number.

131221312102 is a deficient number, since it is larger than the sum of its proper divisors (65610656054).

131221312102 is an equidigital number, since it uses as much as digits as its factorization.

131221312102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65610656053.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 131221312102 its reverse (201213122131), we get a palindrome (332434434233).

The spelling of 131221312102 in words is "one hundred thirty-one billion, two hundred twenty-one million, three hundred twelve thousand, one hundred two".

Divisors: 1 2 65610656051 131221312102