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131221327253 = 443296210671
BaseRepresentation
bin111101000110101100…
…1101000110110010101
3110112201001002002122112
41322031121220312111
54122220124433003
6140140544240405
712323533610132
oct1721531506625
9415631062575
10131221327253
11507180223a5
1221521910105
13c4b2c25593
1464cb78b589
1536301b33d8
hex1e8d668d95

131221327253 has 4 divisors (see below), whose sum is σ = 131517538368. Its totient is φ = 130925116140.

The previous prime is 131221327229. The next prime is 131221327273. The reversal of 131221327253 is 352723122131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131221327253 - 220 = 131220278677 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131221327213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 148104893 + ... + 148105778.

It is an arithmetic number, because the mean of its divisors is an integer number (32879384592).

Almost surely, 2131221327253 is an apocalyptic number.

It is an amenable number.

131221327253 is a deficient number, since it is larger than the sum of its proper divisors (296211115).

131221327253 is an equidigital number, since it uses as much as digits as its factorization.

131221327253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 296211114.

The product of its digits is 15120, while the sum is 32.

Adding to 131221327253 its reverse (352723122131), we get a palindrome (483944449384).

The spelling of 131221327253 in words is "one hundred thirty-one billion, two hundred twenty-one million, three hundred twenty-seven thousand, two hundred fifty-three".

Divisors: 1 443 296210671 131221327253