Base | Representation |
---|---|
bin | 1011111011110011110010… |
… | …1100110001111011000111 |
3 | 1201110110112201222020120201 |
4 | 2332330330230301323013 |
5 | 3204443122211223223 |
6 | 43524121322511331 |
7 | 2523020643032410 |
oct | 276747454617307 |
9 | 51413481866521 |
10 | 13122143461063 |
11 | 41aa08498793a |
12 | 157b1ab365547 |
13 | 742549c69630 |
14 | 335187ccc807 |
15 | 17b50c8dbead |
hex | bef3cb31ec7 |
13122143461063 has 16 divisors (see below), whose sum is σ = 16211738543616. Its totient is φ = 10342878611040.
The previous prime is 13122143461033. The next prime is 13122143461117. The reversal of 13122143461063 is 36016434122131.
It is a cyclic number.
It is not a de Polignac number, because 13122143461063 - 29 = 13122143460551 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13122143461003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 274119373 + ... + 274167238.
It is an arithmetic number, because the mean of its divisors is an integer number (1013233658976).
Almost surely, 213122143461063 is an apocalyptic number.
13122143461063 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13122143461063 is a deficient number, since it is larger than the sum of its proper divisors (3089595082553).
13122143461063 is a wasteful number, since it uses less digits than its factorization.
13122143461063 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 548286894.
The product of its (nonzero) digits is 62208, while the sum is 37.
Adding to 13122143461063 its reverse (36016434122131), we get a palindrome (49138577583194).
The spelling of 13122143461063 in words is "thirteen trillion, one hundred twenty-two billion, one hundred forty-three million, four hundred sixty-one thousand, sixty-three".
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